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Inner bug: TypeError: __init__() got an unexpected keyword argument 'escape_forward_slashes' #2740

@ArdenL

Description

@ArdenL

Is there an existing issue for this?

  • I have searched the existing issues

Describe the bug

i'm not sure if this is a bug, a internal exception occurred when i try to access the inspector page(http://localhost:6457/),

pkgs version:
sanic 23.3.0
sanic-ext 23.3.0
sanic-routing 22.8.0

log:

[ERROR] Exception occurred while handling uri: 'http://localhost:6457/'
Traceback (most recent call last):
  File "handle_request", line 97, in handle_request
    from sanic_ext.extensions.base import Extension  # type: ignore
  File "D:\apps\Anaconda\envs\sanic\lib\site-packages\sanic\worker\inspector.py", line 82, in _info
    return await self._respond(request, self._state_to_json())
  File "D:\apps\Anaconda\envs\sanic\lib\site-packages\sanic\worker\inspector.py", line 86, in _respond
    return json(
  File "D:\apps\Anaconda\envs\sanic\lib\site-packages\sanic\response\convenience.py", line 50, in json
    return JSONResponse(
  File "D:\apps\Anaconda\envs\sanic\lib\site-packages\sanic\response\types.py", line 361, in __init__
    self._encode_body(self._use_dumps(body, **self._use_dumps_kwargs)),
  File "D:\apps\Anaconda\envs\sanic\lib\json\__init__.py", line 234, in dumps
    return cls(
TypeError: __init__() got an unexpected keyword argument 'escape_forward_slashes'

Code snippet

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Expected Behavior

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How do you run Sanic?

As a script (app.run or Sanic.serve)

Operating System

windows

Sanic Version

Sanic 23.3.0; Routing 22.8.0

Additional context

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