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In the explanation of Fig 5-11 on page 96, we have:
Note that for some values of
a
, subtracting 3 froma
will cause its lowest-weight qubit to be set. We can use this top bit as a condition for our increment operation.
Emphasis mine.
I'm reading this as referring to the not
s in the if (a<0) then b++
block being conditioned over 0x4 (for a
). Should this be the most significant qubit?
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