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Aliases are lost when conditionals are applied #61581

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@mikearnaldi

Description

@mikearnaldi

🔎 Search Terms

aliases lost

🕗 Version & Regression Information

Discussion with @Andarist:

Anyway, I'm sort of leaving breadcrumbs for myself - sorry for oversharing 😉 I'll dig further later

⏯ Playground Link

https://www.typescriptlang.org/play/?#code/C4TwDgpgBAShDOBXANsAPAQQDRQKID4oBeKAbwCgoqoAnCAQwBMB7AO2RCgH1h6BzAFxQARAHkA1sMrU6TNhygA3eskQQhGcgF8oAHzLSqslu049+Q4QDF6AS2RTqtBiYUQaNZjSG5t5cowQAMbI9HRQQWzwwFC28HBIqEIAFIhCiKzirMwA7qwAlMSEiLHwsAgo6PSsIDjVIPj+kazRUABmrMRQmDgEybasYEIJlT14hPrRNAN8hUSEcSOo-YOFAPyxg1CWzJJAA

💻 Code

type Result<A, E> = {
    readonly _tag: "Ok"
    readonly value: A
} | {
    readonly _tag: "Fail"
    readonly error: E
}

declare const isResult: (u: unknown) => u is Result<any, any>

const fn = <A, E>(inp: Result<A, E> | string) => isResult(inp) ? inp : "ok"

🙁 Actual behavior

const fn: <A, E>(inp: Result<A, E> | string) => {
    readonly _tag: "Ok";
    readonly value: A;
} | {
    readonly _tag: "Fail";
    readonly error: E;
} | "ok"

🙂 Expected behavior

const fn: <A, E>(inp: Result<A, E> | string) => Result<A, E> | "ok"

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    Help WantedYou can do thisPossible ImprovementThe current behavior isn't wrong, but it's possible to see that it might be better in some cases

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