Closed
Description
from `db.t`
derive d = create_time + 1
group d (
aggregate [
n1 = (a | sum),
]
)
sort d
select [ d1 = d, n1 ]
generates the result:
SELECT
create_time + 1 AS d1,
SUM(a) AS n1,
create_time + 1 AS _expr_0
FROM
db.t
GROUP BY
create_time + 1
ORDER BY
_expr_0
-- Generated by PRQL compiler version:0.6.0 (https://prql-lang.org)
- if select with group key, the key is added. (correct)
- if select without group key,
_expr_0
is added. (correct. but not good) - if select with group key alias,
_expr_0
is added. (wrong)