035. Find Number with even number of digits.py

# Find Number with even number of digits    
"""
Given an array nums of integers, return how many of them contain an even number of digits.
 

Example 1:

Input: nums = [12,345,2,6,7896]
Output: 2
Explanation: 
12 contains 2 digits (even number of digits). 
345 contains 3 digits (odd number of digits). 
2 contains 1 digit (odd number of digits). 
6 contains 1 digit (odd number of digits). 
7896 contains 4 digits (even number of digits). 
Therefore only 12 and 7896 contain an even number of digits.
"""


def findNumbers(self, nums):
        """
        :type nums: List[int]
        :rtype: int
        """
        count = 0
        for num in nums:
            if len(str(num))%2==0:
                count+=1
        return count