You signed in with another tab or window. Reload to refresh your session.You signed out in another tab or window. Reload to refresh your session.You switched accounts on another tab or window. Reload to refresh your session.Dismiss alert
[ctrmgr]: Container image clean up bug fix (#15772)
Why I did it
When do clean up container images, current code has two bugs need to be fixed. And some variables' name maybe cause confused, change the variables' name.
Work item tracking
Microsoft ADO (number only): 24502294
How I did it
We do clean up after tag latest successfully. But currently tag latest function only return 0 and 1, 0 means succeed and 1 means failed, when we get 1, we will retry, when we get 0, we will do clean up. Actually the code 0 includes another case we don't need to do clean up. The case is that when we are doing tag latest, the container image we want to tag maybe not running, so we can not tag latest and don't need to cleanup, we need to separate this case from 0, return -1 now.
When local mode(v1) -> kube mode(v2) happens, one problem is how to handle the local image, there are two cases. one case is that there was one kube v1 container dry-run(cause we don't relace the local if kube version = local version), we will remove the kube v1 image and tag the local version with ACR prefix and remove local v1 local tag. Another case is that there was no kube v1 container dry-run, we remove the local v1 image directly, cause the local v1 image should not be the last desire version.
About the docker_id variable, it may cause confused, it's actually docker image id, so rename the variable. About the two dicts and the list, rename them to be more readable.
How to verify it
Check tag latest and image clean up result.
0 commit comments