multiple elifs will fail #19

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JoePelz opened this issue Nov 17, 2015 · 1 comment

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bug

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JoePelz commented Nov 17, 2015

The issue is with multiple elif statements, if a previous statement has already run.
The following will generate erroneous output:

x = 1
y = 1
x == 1 && y == 1 if
  echo "x=1 y=1, "
? elif x == 1
  echo "x=1 y!=1, "
? elif y == 1
  echo "x!=1 y=1, "
? else
  echo "x!=1 y!=1, "

It will print x=1 y=1, x!=1, y=1 rather than the expected x=1 y=1,
No workaround right now.

The fix may be to apply DeMorgan's Law on the second or later elif when negating the previous condition.

The text was updated successfully, but these errors were encountered:

JoePelz added the bug label

Contributor Author

JoePelz commented Nov 20, 2015

Workaround right now is discrete if statements

x == 1 && y == 1 if
  echo "x=1 y=1, "
y!=1 && x==1 if
  echo "x=1 y!=1, "
y==1 && x!=1 if
  echo "x!=1 y=1, "
x!=1 && y!=1 else
  echo "x!=1 y!=1, "

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